Beautifulsoup obtenir span contenu

J'ai analysé page html: utilisation de beautifulsoup

user_page = urllib2.urlopen(user_url)
souping_page = bs(user_page)
badges = souping_page.body.find('div', attrs={'class': 'badges'})

après mon badges objet ressemble à ceci:

<span><span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span><span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span><span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span></span>

Maintenant je veux extraire exemple 9 gold badges, 38 silver badges à partir de cela, j'ai essayé d'utiliser badges.span.span mais qui ne fonctionne pas.

OriginalL'auteur add-semi-colons | 2014-03-07

  1. 10

    Obtenir le parent span de badges, trouvez tous les haut-niveau s'étend à l'intérieur en utilisant find_all() avec recursive=False:

    from bs4 import BeautifulSoup


page = """<div class="badges">
<span>
    <span title="9 gold badges"><span class="badge1"></span><span class="badgecount">9</span></span>
    <span title="38 silver badges"><span class="badge2"></span><span class="badgecount">38</span></span>
    <span title="56 bronze badges"><span class="badge3"></span><span class="badgecount">56</span></span>
</span>
</div>"""

soup = BeautifulSoup(page)
badges = soup.body.find('div', attrs={'class': 'badges'})
for span in badges.span.find_all('span', recursive=False):
    print span.attrs['title']

    imprime:

    9 gold badges
38 silver badges
56 bronze badges

    Espère que ça aide.

    OriginalL'auteur alecxe