Comment puis-je valider un timestamp?

Je ne suis pas sûr de savoir exactement sur le format, mais vous vous pouvez jouer autour d'elle et d'essayer quelque chose de ce genre

public static bool isTimeStampValid(String inputString)
{ 
    SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
    try{
       format.parse(inputString);
       return true;
    }
    catch(ParseException e)
    {
        return false;
    }
}

EDIT: si vous souhaitez valider les chiffres après le succès de l'analyse, vous pourriez faire

       format.parse(inputString);
       Pattern p = Pattern.compile("^\\d{4}[-]?\\d{1,2}[-]?\\d{1,2} \\d{1,2}:\\d{1,2}:\\d{1,2}[.]?\\d{1,6}$");
       return p.matcher(inputString).matches();

au lieu de

   format.parse(inputString);
   return true;

/**
* This method validates the given time stamp in String format
* @param timestamp
* @return
*/
public static boolean isTimeStampValid(String timestamp) {
//(Considering that formal will be yyyy-MM-dd HH:mm:ss.SSSSSS )
//Tokenize string and separate date and time
boolean time = false;
try {
//Tokenize string and separate date and time
StringTokenizer st = new StringTokenizer(timestamp, " ");
if (st.countTokens() != 2) {
return false;
}
String[] dateAndTime = new String[2];
int i = 0;
while (st.hasMoreTokens()) {
dateAndTime[i] = st.nextToken();
i++;
}
String timeToken = dateAndTime[1];
StringTokenizer timeTokens = new StringTokenizer(timeToken, ":");
if (timeTokens.countTokens() != 3) {
return false;
}
String[] timeAt = new String[4];
int j = 0;
while (timeTokens.hasMoreTokens()) {
timeAt[j] = timeTokens.nextToken();
j++;
}
try {
int HH = Integer.valueOf(timeAt[0].toString());
int mm = Integer.valueOf(timeAt[1].toString());
float ss = Float.valueOf(timeAt[2].toString());
if (HH < 60 && HH >= 0 && mm < 60 && mm >= 0 && ss < 60 && ss >= 0) {
time = true;
} else {
}
} catch (Exception e) {
e.printStackTrace();
}
//Got Date
String dateToken = dateAndTime[0];//st.nextToken();
//Tokenize separated date and separate year-month-day
StringTokenizer dateTokens = new StringTokenizer(dateToken, "-");
if (dateTokens.countTokens() != 3) {
return false;
}
String[] tokenAt = new String[3];
//This will give token string array with year month and day value.
int k = 0;
while (dateTokens.hasMoreTokens()) {
tokenAt[k] = dateTokens.nextToken();
k++;
}
//Now try to create new date with got value of date
int dayInt = Integer.parseInt(tokenAt[2]);
int monthInt = Integer.parseInt(tokenAt[1]);
int yearInt = Integer.parseInt(tokenAt[0]);
Calendar cal = new GregorianCalendar();
cal.setLenient(false);
cal.set(yearInt, monthInt - 1, dayInt);
cal.getTime();//If not able to create date it will throw error
} catch (Exception e) {
e.printStackTrace();
return false;
}
//Here we ll check for correct format is provided else it ll return false
try {
Pattern p = Pattern.compile("^\\d{4}[-]?\\d{1,2}[-]?\\d{1,2} \\d{1,2}:\\d{1,2}:\\d{1,2}[.]?\\d{1,6}$");
if (p.matcher(timestamp).matches()) {
} else {
return false;
}
} catch (Exception e) {
e.printStackTrace();
return false;
}
//Cross checking with simple date format to get correct time stamp only
SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS");
try {
format.parse(timestamp);
//return true;
if (time) {
return true;
} else {
return false;
}
} catch (ParseException e) {
e.printStackTrace();
return false;
} catch (Exception e) {
e.printStackTrace();
return false;
}
}