Comment travailler sur jqgrid Ajouter, modifier, supprimer? à l'aide de php
comment travailler sur ajouter une ligne, d'éditer, de del de la ligne de jqgrid? comment appeler editurl??
mon code est ci-dessous... jqgrid.php page.
var $mygrid= jQuery("#list").jqGrid({
url:'example.php',
datatype: 'xml',
mtype: 'GET',
colNames:['Seq','Name', 'ID','Pass','Mail','Note'],
colModel :[
{name:'seq',index:'seq', width:55, resizable:false, editable:true, editoptions:{readonly:true,size:10}},
{name:'name',index:'name', width:90,resizable:false, editable:true, editoptions:{readonly:false,size:10}},
{name:'id',index:'id', width:80, align:'right', editable:true, editoptions:{readonly:false,size:10}},
{name:'pass',index:'pass', width:80, align:'right', sortable:false, editable:true, editoptions:{readonly:false,size:10}},
{name:'mail',index:'mail', width:80,align:'right', sortable:false, editable:true, editoptions:{readonly:false,size:10}},
{name:'id',index:'id', width:150, sortable:false} ],
pager: jQuery('#pager'),
rowNum:10,
rowList:[10,20,30,50],
sortname: 'seq',
sortorder: "Asc",
width: 1000,
height: 230,
viewrecords: true,
multiselect: true,
editable: true,
toolbar: [true,"top"],
multikey: "ctrlKey",
editurl:'add.php',
caption: 'staff'
});
$("#list").jqGrid('navGrid', '#pager', {
edit: true,
add: true,
del: true,
search: false,
refresh:false
})
});
Et example.php le code est
enter code here <?php
$dbhost = 'localhost';
$dbuser = 'test';
$dbpassword = 'test';
$database = 'cs_test';
$page = $_GET['page'];
//get how many rows we want to have into the grid - rowNum parameter in the grid
$limit = $_GET['rows'];
//get index row - i.e. user click to sort. At first time sortname parameter -
//after that the index from colModel
$sidx = $_GET['sidx'];
//sorting order - at first time sortorder
$sord = $_GET['sord'];
//if we not pass at first time index use the first column for the index or what you want
if(!$sidx) $sidx =1;
//connect to the MySQL database server
$db = mysql_connect($dbhost, $dbuser, $dbpassword) or die("Connection Error: " . mysql_error());
//select the database
mysql_select_db($database) or die("Error conecting to db.");
//calculate the number of rows for the query. We need this to paging the result
$result = mysql_query("SELECT COUNT(*) AS count FROM TM_Staff");
$row = mysql_fetch_array($result,MYSQL_ASSOC);
$count = $row['count'];
//calculation of total pages for the query
if( $count > 0 ) {
$total_pages = ceil($count/$limit);
//$total_pages = 20;
} else {
$total_pages = 0;
}
if ($page > $total_pages) $page=$total_pages;
$start = $limit*$page - $limit;
if($start<0) $start = 0;
//the actual query for the grid data
$SQL = "SELECT seq,name,id,pass,mail,ins_dt from TM_Staff ORDER BY $sidx $sord LIMIT $start,$limit";
$result = mysql_query( $SQL ) or die("Couldn t execute query.".mysql_error());
if ( stristr($_SERVER["HTTP_ACCEPT"],"application/xhtml+xml") ) {
header("Content-type: application/xhtml+xml;charset=utf-8");
} else {
header("Content-type: text/xml;charset=utf-8");
}
echo "<?xml version='1.0' encoding='utf-8'?>";
echo "<rows>";
echo "<page>".$page."</page>";
echo "<total>".$total_pages."</total>";
echo "<records>".$count."</records>";
//be sure to put text data in CDATA
while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
echo "<row id='". $row[seq]."'>";
echo "<cell>". $row[seq]."</cell>";
echo "<cell>". $row[name]."</cell>";
echo "<cell>". $row[id]."</cell>";
echo "<cell>". $row[pass]."</cell>";
echo "<cell>". $row[mail]."</cell>";
echo "<cell><![CDATA[". $row[id]."]]></cell>";
echo "</row>";
}
echo "</rows>";
?>
plz help me, im en difficulté...
OriginalL'auteur Steve | 2010-07-02
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OriginalL'auteur jitendra
Dans edit.php vous devez le mettre comme ceci:
Si vous voulez voir ce que vous obtenez, utilisation:
print_r($_REQUEST);OriginalL'auteur ssgodfather
Dans edit.php
OriginalL'auteur Tareq
J'aime vraiment l'idée de PHPjq cependant le code qu'ils sont "vente" ne pas avoir les meilleures pratiques pour prévenir l'injection SQL. afin d'acheter leur code et ajouter la bonne sql échapper wrappers ou écrire votre propre .... être sûr de ne pas paresseux.
OriginalL'auteur derek