Httpclient à enregistrer à l'aide multipart/form-data

J'ai besoin de charger une image. Pour ce que j'ai à passer de l'image & id sur le serveur :

dos.writeBytes("Content-Disposition: form-data; name=\"file_name\";filename=\""
            + fileName + "\"" + lineEnd);


        dos.writeBytes("Content-Disposition: form-data; name=\"" + stringFieldName + "\""+ lineEnd);
        dos.writeBytes(lineEnd);

nom de fichier est le chemin de l'image
stringFieldName est le user_id

Mon code est donné ci-dessous

 public void webservicePhp(Long userId, Bitmap bmp) {
String userIdParameter = String.valueOf(userId);
String fileName = "temporary_holder.jpg";
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
String charset = "UTF-8";
String responseFromServer = "";
String stringFieldName = "user_id";
String sourceFileUri = HomeScreen.get_path();
String upLoadServerUri = "http://10.120.10.87:8080/ContactsManagerWeb/UploadImage";
File sourceFile = new File(sourceFileUri);
if (!sourceFile.isFile()) {
Log.e("Huzza", "Source File Does not exist");
return;
}
int serverResponseCode = 0;
try { //open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
conn = (HttpURLConnection) url.openConnection(); //Open a HTTP
//connection to
//the URL
conn.setDoInput(true); //Allow Inputs
conn.setDoOutput(true); //Allow Outputs
conn.setUseCaches(false); //Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Accept-Charset", charset);
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("file_name", fileName);
conn.setRequestProperty("user_id", userIdParameter);
dos = new DataOutputStream(conn.getOutputStream());
dos.write(query.getBytes(charset));
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"file_name\";filename=\""
+ fileName + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"" + stringFieldName + "\""+ lineEnd);
dos.writeBytes(lineEnd);
bytesAvailable = fileInputStream.available(); //create a buffer of
//maximum size
bufferSize = (int) sourceFile.length();
System.out.println("BytesAvail" + bytesAvailable);
System.out.println("maxBufferSize" + maxBufferSize);
buffer = new byte[bufferSize];
//read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
//send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
//Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
System.out.println("Upload file to serverHTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
//close streams
System.out.println("Upload file to server"+ fileName + " File is written");
fileInputStream.close();
dos.flush();
dos.close();
} catch (MalformedURLException ex) {
ex.printStackTrace();
Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
} catch (Exception e) {
e.printStackTrace();
}
//this block will give the response of upload link
try {
BufferedReader rd = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
System.out.println("RESULT Message: " + line);
}
rd.close();
} catch (IOException ioex) {
Log.e("Huzza", "error: " + ioex.getMessage(), ioex);
}
return; //like 200 (Ok)
}
}

Dans ma servlet je ne peux pas en mesure d'accéder à l'user_id paramètre. Ses pas y arriver

Servlet.java

public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();    
File filenameImg = null;
List<FileItem> items = null;
try {
items = new ServletFileUpload(new DiskFileItemFactory())
.parseRequest(request);
} catch (FileUploadException e) {
throw new ServletException("Cannot parse multipart request.", e);
}
for (FileItem item : items) {
if (item.isFormField()) {
//Process regular form fields here the same way as
//request.getParameter().
//You can get parameter name by
String fieldname = item.getFieldName();       
String fieldvalue = item.getString(); 
System.out.println("user_id===fieldname====== "+fieldname);
System.out.println("user_id====fieldvalue===== "+fieldvalue);
//You can get parameter value by item.getString();
} else {
try{
//Process uploaded fields here.
String filename = FilenameUtils.getName(item.getName());
//Get filename.
String path = GetWebApplicationPathServlet.getContext().getRealPath("/images");
File file =  new File(path,filename);
//File file = new File("C:\\", filename);
//Define destination file.
item.write(file);
System.out.println("filename: "+filename);
System.out.println("file: "+file);
request.setAttribute("image", file);
filenameImg = file;
//Write to destination file.
// request.setAttribute("image", filename);
}
catch (Exception e) {
e.printStackTrace();
}
}
}
//Show result page.
System.out.println("request"+request.getAttribute("image"));
//response.setContentType("image/jpeg"); 
request.setAttribute("servletName", filenameImg);
getServletConfig().getServletContext().getRequestDispatcher(
"/result.jsp").forward(request,response);
}
if (item.isFormField()) {} is retuned as false : 

S'Il Vous Plaît Aider

  • Salut jennifer pourrait s'il vous plaît commentaire comment avez-vous déclarer query sur cette ligne dos.write(query.getBytes(charset));. J'ai un problème d'envoi de paramètres avec upload de fichier vers le serveur. Je suis en train de modifier mon code en fonction de ce fil.
InformationsquelleAutor jennifer | 2011-04-04