Le premier argument de copie() la fonction ne peut pas être un répertoire?

    $base = dirname(__FILE__).'/themes/';
    $target = dirname( STYLESHEETPATH ).'/';
    $directory_folders = new DirectoryIterator($base); 
    foreach ($directory_folders as $folder) 
    {
        if (!$folder->isDot())           {

            echo '<p>source: '.$folder->getRealPath();
            //returns: C:\xampplite\htdocs\test\wp-content\plugins\test\themes\testtheme-1

            echo '<br>target: '.$target;
            //returns: C:\xampplite\htdocs\test/wp-content/themes/

            copy($folder->getRealPath(), $target);
            //returns: Error. The first argument to copy() function cannot be a directory
         }
    }die;

Mise À JOUR: le Pascal proposition de réponse, voici mon code amendé. Les travaux de cette.

function recurse_copy(){
    $src = dirname(__FILE__).'/themes/';
    $dst = dirname( STYLESHEETPATH ).'/';

    $dir = opendir($src); 
    @mkdir($dst); 
    while(false !== ( $file = readdir($dir)) ) 
    { 
        if (( $file != '.' ) && ( $file != '..' )) 
        { 
            if ( is_dir($src . '/' . $file) ) { 
                recurse_copy_recurse($src . '/' . $file,$dst . '/' . $file); 
            } 
            else { 
                copy($src . '/' . $file,$dst . '/' . $file); 
            } 
        } 
    } 
    closedir($dir); 
}


function recurse_copy_recurse($src,$dst){

    $dir = opendir($src); 
    @mkdir($dst); 
    while(false !== ( $file = readdir($dir)) ) 
    { 
        if (( $file != '.' ) && ( $file != '..' )) 
        { 
            if ( is_dir($src . '/' . $file) ) { 
                recurse_copy_recurse($src . '/' . $file,$dst . '/' . $file); 
            } 
            else { 
                copy($src . '/' . $file,$dst . '/' . $file); 
            } 
        } 
    } 
    closedir($dir); 
}
InformationsquelleAutor Scott B | 2011-03-24