Les colonnes de la liste avec les index dans PostgreSQL

Créer des données de test...

create table test (a int, b int, c int, constraint pk_test primary key(a, b));
create table test2 (a int, b int, c int, constraint uk_test2 unique (b, c));
create table test3 (a int, b int, c int, constraint uk_test3b unique (b), constraint uk_test3c unique (c),constraint uk_test3ab unique (a, b));

Liste des index et des colonnes indexées:

select
    t.relname as table_name,
    i.relname as index_name,
    a.attname as column_name
from
    pg_class t,
    pg_class i,
    pg_index ix,
    pg_attribute a
where
    t.oid = ix.indrelid
    and i.oid = ix.indexrelid
    and a.attrelid = t.oid
    and a.attnum = ANY(ix.indkey)
    and t.relkind = 'r'
    and t.relname like 'test%'
order by
    t.relname,
    i.relname;

 table_name | index_name | column_name
------------+------------+-------------
 test       | pk_test    | a
 test       | pk_test    | b
 test2      | uk_test2   | b
 test2      | uk_test2   | c
 test3      | uk_test3ab | a
 test3      | uk_test3ab | b
 test3      | uk_test3b  | b
 test3      | uk_test3c  | c

Retrousser les noms de colonne:

select
    t.relname as table_name,
    i.relname as index_name,
    array_to_string(array_agg(a.attname), ', ') as column_names
from
    pg_class t,
    pg_class i,
    pg_index ix,
    pg_attribute a
where
    t.oid = ix.indrelid
    and i.oid = ix.indexrelid
    and a.attrelid = t.oid
    and a.attnum = ANY(ix.indkey)
    and t.relkind = 'r'
    and t.relname like 'test%'
group by
    t.relname,
    i.relname
order by
    t.relname,
    i.relname;

 table_name | index_name | column_names
------------+------------+--------------
 test       | pk_test    | a, b
 test2      | uk_test2   | b, c
 test3      | uk_test3ab | a, b
 test3      | uk_test3b  | b
 test3      | uk_test3c  | c

PostgreSQL (pg_indexes):

SELECT * FROM pg_indexes WHERE tablename = 'mytable';

MySQL (VOIR L'INDEX):

SHOW INDEX FROM mytable;

# \di

La easies et le plus court chemin est \di, qui fournira la liste de tous les index de la base de données actuelle.

$ \di
                      List of relations
 Schema |            Name             | Type  |  Owner   |     Table     
--------+-----------------------------+-------+----------+---------------
 public | part_delivery_index         | index | shipper  | part_delivery
 public | part_delivery_pkey          | index | shipper  | part_delivery
 public | shipment_by_mandator        | index | shipper  | shipment_info
 public | shipment_by_number_and_size | index | shipper  | shipment_info
 public | shipment_info_pkey          | index | shipper  | shipment_info
(5 rows)

\di est le "petit frère" de la \d de commande qui liste l'ensemble des relations de l'actuel database. Ainsi \di certainement stand pour "montrez-moi ce databases jendexes".

Tapant \diS liste de tous les indices utilisés à l'échelle du système, ce qui signifie que vous obtenez tous les pg_catalog ainsi les index.

$ \diS
                                      List of relations
   Schema   |                   Name                    | Type  |  Owner   |          Table
------------+-------------------------------------------+-------+----------+-------------------------
 pg_catalog | pg_aggregate_fnoid_index                  | index | postgres | pg_aggregate
 pg_catalog | pg_am_name_index                          | index | postgres | pg_am
 pg_catalog | pg_am_oid_index                           | index | postgres | pg_am
 pg_catalog | pg_amop_fam_strat_index                   | index | postgres | pg_amop
 pg_catalog | pg_amop_oid_index                         | index | postgres | pg_amop
 pg_catalog | pg_amop_opr_fam_index                     | index | postgres | pg_amop
 pg_catalog | pg_amproc_fam_proc_index                  | index | postgres | pg_amproc
 pg_catalog | pg_amproc_oid_index                       | index | postgres | pg_amproc
 pg_catalog | pg_attrdef_adrelid_adnum_index            | index | postgres | pg_attrdef
--More-- 

Avec ces deux commandes, vous pouvez ajouter un + après pour obtenir encore plus d'informations, comme la taille de l'espace disque de l'indice de besoins et une description si disponible.

$ \di+
                                 List of relations
 Schema |            Name             | Type  |  Owner   |     Table     | Size  | Description 
--------+-----------------------------+-------+----------+---------------+-------+-------------
 public | part_delivery_index         | index | shipper  | part_delivery | 16 kB | 
 public | part_delivery_pkey          | index | shipper  | part_delivery | 16 kB | 
 public | shipment_by_mandator        | index | shipper  | shipment_info | 19 MB | 
 public | shipment_by_number_and_size | index | shipper  | shipment_info | 19 MB | 
 public | shipment_info_pkey          | index | shipper  | shipment_info | 53 MB | 
(5 rows)

Dans psql, vous pouvez facilement trouver de l'aide sur les commandes à taper \?.

Quelques exemples de données...

create table test (a int, b int, c int, constraint pk_test primary key(a, b));
create table test2 (a int, b int, c int, constraint uk_test2 unique (b, c));
create table test3 (a int, b int, c int, constraint uk_test3b unique (b), constraint uk_test3c unique (c), constraint uk_test3ab unique (a, b));

Utilisation pg_get_indexdef fonction:

select pg_get_indexdef(indexrelid) from pg_index where indrelid = 'test'::regclass;

                    pg_get_indexdef
--------------------------------------------------------
 CREATE UNIQUE INDEX pk_test ON test USING btree (a, b)
(1 row)


select pg_get_indexdef(indexrelid) from pg_index where indrelid = 'test2'::regclass;
                     pg_get_indexdef
----------------------------------------------------------
 CREATE UNIQUE INDEX uk_test2 ON test2 USING btree (b, c)
(1 row)


select pg_get_indexdef(indexrelid) from pg_index where indrelid ='test3'::regclass;
                      pg_get_indexdef
------------------------------------------------------------
 CREATE UNIQUE INDEX uk_test3b ON test3 USING btree (b)
 CREATE UNIQUE INDEX uk_test3c ON test3 USING btree (c)
 CREATE UNIQUE INDEX uk_test3ab ON test3 USING btree (a, b)
(3 rows)

\d tablename montre les noms de colonne pour moi sur la version 8.3.8.

 "username_idx" UNIQUE, btree (username), tablespace "alldata1"

Les premières info est pg_index.

En jouant avec des indices de l'ordre dans lequel les colonnes sont construits dans l'index est aussi important que les colonnes elles-mêmes.

La requête suivante répertorie tous les index d'une table donnée, et tous leurs colonnes triées de la mode.

SELECT
table_name,
index_name,
string_agg(column_name, ',')
FROM (
SELECT
t.relname AS table_name,
i.relname AS index_name,
a.attname AS column_name,
(SELECT i
FROM (SELECT
*,
row_number()
OVER () i
FROM unnest(indkey) WITH ORDINALITY AS a(v)) a
WHERE v = attnum)
FROM
pg_class t,
pg_class i,
pg_index ix,
pg_attribute a
WHERE
t.oid = ix.indrelid
AND i.oid = ix.indexrelid
AND a.attrelid = t.oid
AND a.attnum = ANY (ix.indkey)
AND t.relkind = 'r'
AND t.relname LIKE 'tablename'
ORDER BY table_name, index_name, i
) raw
GROUP BY table_name, index_name

Similaire à la accepté de répondre, mais ayant left join sur pg_attribute comme normal de se joindre ou de la requête avec pg_attribute ne marche pas donner d'indices, qui sont comme des :

create unique index unique_user_name_index on users (lower(name))

select 
row_number() over (order by c.relname),
c.relname as index, 
t.relname as table, 
array_to_string(array_agg(a.attname), ', ') as column_names 
from pg_class c
join pg_index i on c.oid = i.indexrelid and c.relkind='i' and c.relname not like 'pg_%' 
join pg_class t on t.oid = i.indrelid
left join pg_attribute a on a.attrelid = t.oid and a.attnum = ANY(i.indkey) 
group by t.relname, c.relname order by c.relname;

Quelle est la solution la plus simple:

SELECT 
t.relname table_name,
ix.relname index_name,
indisunique,
indisprimary, 
regexp_replace(pg_get_indexdef(indexrelid), '.*\((.*)\)', '\1') columns
FROM pg_index i
JOIN pg_class t ON t.oid = i.indrelid
JOIN pg_class ix ON ix.oid = i.indexrelid
WHERE t.relname LIKE 'test%'

`

Je ne pense pas que cette version existe sur ce fil encore: il fournit la liste des noms de colonnes avec le ddl pour l'index.

CREATE OR REPLACE VIEW V_TABLE_INDEXES AS
SELECT
n.nspname  as "schema"
,t.relname  as "table"
,c.relname  as "index"
,i.indisunique AS "is_unique"
,array_to_string(array_agg(a.attname), ', ') as "columns"
,pg_get_indexdef(i.indexrelid) as "ddl"
FROM pg_catalog.pg_class c
JOIN pg_catalog.pg_namespace n ON n.oid        = c.relnamespace
JOIN pg_catalog.pg_index i ON i.indexrelid = c.oid
JOIN pg_catalog.pg_class t ON i.indrelid   = t.oid
JOIN pg_attribute a ON a.attrelid = t.oid AND a.attnum = ANY(i.indkey)
WHERE c.relkind = 'i'
and n.nspname not in ('pg_catalog', 'pg_toast')
and pg_catalog.pg_table_is_visible(c.oid)
GROUP BY
n.nspname
,t.relname
,c.relname
,i.indisunique
,i.indexrelid
ORDER BY
n.nspname
,t.relname
,c.relname;

J'ai trouvé que l'index à l'aide de fonctions de ne pas accéder à des noms de colonne, de sorte occasionnellement, vous trouverez un index de liste par exemple, un nom de colonne quand, en fait, est utilise 3.

Exemple:

CREATE INDEX ui1 ON table1 (coalesce(col1,''),coalesce(col2,''),col3)

La requête renvoie seulement "col3" comme une colonne de l'index, mais le DDL montre l'ensemble des colonnes utilisées dans l'indice.

Un peu modifié la réponse de @cope360:

create table test (a int, b int, c int, constraint pk_test primary key(c, a, b));
select i.relname as index_name,
ix.indisunique as is_unique,
a.attname as column_name,
from pg_class c
inner join pg_index ix on c.oid=ix.indrelid
inner join pg_class i on ix.indexrelid=i.oid
inner join pg_attribute a on a.attrelid=c.oid and a.attnum=any(ix.indkey)
where c.oid='public.test'::regclass::oid
order by array_position(ix.indkey, a.attnum) asc;

Cela permettra de montrer les colonnes d'index dans l'ordre correct:

index_name      is_unique  column_name
pk_test         true       c
pk_test         true       a
pk_test         true       b

La accepté de répondre à par @cope360 est bon, mais je voulais quelque chose d'un peu plus comme Oracle DBA_IND_COLUMNS, ALL_IND_COLUMNS, et USER_IND_COLUMNS (par exemple, les rapports de la table/schéma de l'index et de la position de l'index un index multicolonne), j'ai donc adapté la accepté de répondre à ceci:

with
ind_cols as (
select
n.nspname as schema_name,
t.relname as table_name,
i.relname as index_name,
a.attname as column_name,
1 + array_position(ix.indkey, a.attnum) as column_position
from
pg_catalog.pg_class t
join pg_catalog.pg_attribute a on t.oid    =      a.attrelid 
join pg_catalog.pg_index ix    on t.oid    =     ix.indrelid
join pg_catalog.pg_class i     on a.attnum = any(ix.indkey)
and i.oid    =     ix.indexrelid
join pg_catalog.pg_namespace n on n.oid    =      t.relnamespace
where t.relkind = 'r'
order by
t.relname,
i.relname,
array_position(ix.indkey, a.attnum)
)
select * 
from ind_cols
where schema_name = 'test'
and table_name  = 'indextest'
order by schema_name, table_name
;

Cela donne une sortie comme:

 schema_name | table_name | index_name | column_name | column_position 
-------------+------------+------------+-------------+-----------------
test        | indextest  | testind1   | singleindex |               1
test        | indextest  | testind2   | firstoftwo  |               1
test        | indextest  | testind2   | secondoftwo |               2
(3 rows)