Une Calculatrice Scientifique en C à l'aide de fonctions

J'ai écrit un programme qui a utilisé la plupart des mathématiques.h bibliothèque de fonctions pour la création d'une sorte de calculatrice scientifique. Cependant, je ne suis pas d'obtenir le résultat souhaité. J'ai toujours 0.000000 à la fin de la sortie. Merci de m'aider à identifier mon erreur, je vous Remercie.

#include <stdio.h>
#include <math.h>
#define PI 3.14159265
float sine(float  x);
float cosine(float x);
float tangent(float x);
float sineh(float x);
float cosineh(float x);
float tangenth(float x);
float logten(float x);
float squareroot(float x);
float exponent(float x);
float power(float x,float y);
int main()
{
int x,y,n,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root. 9.exponent 10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x);       break;
case 2: answer = cosine(x);     break;
case 3: answer = tangent(x);    break;
case 4: answer = sineh(x);      break;
case 5: answer = cosineh(x);    break;
case 6: answer = tangenth(x);   break;
case 7: answer = logten(x);     break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x);   break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
return 0;
}
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x*PI/180));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}

InformationsquelleAutor Shail | 2013-03-05

c calculator logic

4

Vous avez déclaré que ces quatre variables comme les entiers:
```
int x,y,n,answer;
```
mais n est le seul qui vous fait traiter comme un entier. Déclarer x, y et answer comme float:
```
int n;
float x, y, answer;
```
InformationsquelleAutor LihO

#include <stdio.h>
#include <math.h>
#include<conio.h>
#define PI 3.14159265
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}
int main(void)
{
int n;
float x,y,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root. 
9.exponent   10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x);       break;
case 2: answer = cosine(x);     break;
case 3: answer = tangent(x);    break;
case 4: answer = sineh(x);      break;
case 5: answer = cosineh(x);    break;
case 6: answer = tangenth(x);   break;
case 7: answer = logten(x);     break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x);   break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
getch();
return 0;
}

InformationsquelleAutor Viva

Si j'active -Wall et -Wconversion, je vois les avertissements suivants, qui, si vous l'avez résolu, permettrait de résoudre votre problème:

foo.c:23:14: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f",&x);
~~  ^~
%d
foo.c:26:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 1: answer = sine(x);       break;
~ ^~~~~~~
foo.c:27:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 2: answer = cosine(x);     break;
~ ^~~~~~~~~
foo.c:28:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 3: answer = tangent(x);    break;
~ ^~~~~~~~~~
foo.c:29:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 4: answer = sineh(x);      break;
~ ^~~~~~~~
foo.c:30:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 5: answer = cosineh(x);    break;
~ ^~~~~~~~~~
foo.c:31:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 6: answer = tangenth(x);   break;
~ ^~~~~~~~~~~
foo.c:32:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 7: answer = logten(x);     break;
~ ^~~~~~~~~
foo.c:33:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 8: answer = squareroot(x); break;
~ ^~~~~~~~~~~~~
foo.c:34:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 9: answer = exponent(x);   break;
~ ^~~~~~~~~~~
foo.c:40:16: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~    ^~
%d
foo.c:40:19: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~     ^~
%d
foo.c:41:12: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
answer = power(x,y);
~ ^~~~~~~~~~
foo.c:44:15: warning: format specifies type 'double' but the argument has type 'int' [-Wformat]
printf("%f",answer);
~~  ^~~~~~
%d
foo.c:51:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sin (x*PI/180));
~~~~~~  ^~~~~~~~~~~~~~
foo.c:55:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (cos (x*PI/180));
~~~~~~  ^~~~~~~~~~~~~~
foo.c:59:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (tan(x*PI/180));
~~~~~~  ^~~~~~~~~~~~~
foo.c:63:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~  ^~~~~~~
foo.c:67:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~  ^~~~~~~
foo.c:71:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~  ^~~~~~~
foo.c:75:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (log10(x));
~~~~~~  ^~~~~~~~
foo.c:79:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sqrt(x));
~~~~~~  ^~~~~~~
foo.c:83:9: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return(exp(x));
~~~~~~ ^~~~~~
foo.c:87:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (pow(x,y));
~~~~~~  ^~~~~~~~
24 warnings generated.

InformationsquelleAutor Bill Lynch

1

Vous avez déclaré x et d'autres variables, comme int. Essayez de déclarer que float au lieu

InformationsquelleAutor Forhad Ahmed
0

Le problème est que le spécificateur de format est incorrect. Changement de tous les %f à %d dans le scanf déclaration.

InformationsquelleAutor s.suriya narasimman

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