Vérifier si la souris est cliqué dans Java

Je suis en train d'écrire une interface graphique en Java. J'ai besoin de savoir comment faire pour vérifier si l'utilisateur clique sur la souris. Je sais comment faire pour vérifier la position de la souris, mais j'ai juste besoin pour vérifier si il est cliqué.

import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
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import java.awt.*;
import java.awt.event.*;
import java.awt.image.*;
import java.io.*;
import javax.imageio.*;
import javax.swing.*;
/**
* This class demonstrates how to load an Image from an external file
*/
public class LoadImageApp extends Component {
BufferedImage img;
public void paint(Graphics g) {
g.drawImage(img, 50, 70, null);
}
public LoadImageApp() {
try {
img = ImageIO.read(new File("strawberry.jpg"));
} catch (IOException e) {
}
}
public Dimension getPreferredSize() {
if (img == null) {
return new Dimension(100,100);
} else {
return new Dimension(img.getWidth(null), img.getHeight(null));
}
}
public static void main(String[] args) throws InterruptedException {
JFrame f = new JFrame("Load Image Sample");
f.addWindowListener(new WindowAdapter(){
public void windowClosing(WindowEvent e) {
System.exit(0);
}
});
f.add(new LoadImageApp());
f.pack();
f.setVisible(true);
f.setResizable(true);
while(true){
Thread.sleep(1000);
PointerInfo a = MouseInfo.getPointerInfo();
Point b = a.getLocation();
int x = (int) b.getX();
int y = (int) b.getY();
System.out.println(x);
System.out.println(y);
}
}
public void mouseClicked(MouseEvent e) {
System.out.println("mouseClicked");  
}
}

c'est tout mon code, donc s'il vous plaît expliquer comment impliment qu'une souris vérificateur de chose.
Merci!

  • Est-ce une application Swing?
  • Euh... je ne pense pas que si il vient:
  • Crée une nouvelle fenêtre. puis il charge d'une image (ou les images) et les affiche sur cette nouvelle fenêtre. Je suis manuellement en faisant des boutons (les images sont les boutons et j'ai l'animation couverts), mais j'ai besoin de prendre le x et le y coords (j'ai le x et y) et vérifier si il est cliqué (je ne sais pas comment faire partie.)
InformationsquelleAutor MezuCobalt | 2013-08-19